New York, NY (SportsNetwork.com) - Golden State Warriors guard Stephen Curry has been selected as the NBA's Most Valuable Player.
Curry became the second Warrior to win the award and first since the club moved to the west coast in 1962. Wilt Chamberlain was honored for the 1959-60 season when the franchise was based in Philadelphia.
The 27-year-old sharpshooter led the Warriors to a franchise-record 67 wins this season and the club's first division title since the 1975-76 campaign. He averaged 23.8 points, 7.7. assists and 4.3 rebounds in 80 games
Curry received 100 first-place votes from a panel of 129 sportswriters and broadcasters, as well as one NBA.com fan vote, for a total of 1,198 points to outdistance Houston's James Harden for the award.
Harden picked up 25 first-place votes and 936 points to finish second in the balloting, well ahead of Cleveland's LeBron James. The four-time MVP earned the other five first-place votes and 552 points.
Curry was the sixth-leading scorer in the NBA and led the league in 3-point field goals for a third consecutive season, hitting 286 from beyond the arc to break his own NBA record for a single season. He also ranked third in 3-point percentage, converting at 44.3 percent and led the league in free throw shooting at 91.4 percent.
Oklahoma City's Russell Westbrook was fourth in the voting, followed by Anthony Davis of New Orleans and Chris Paul of the Los Angeles Clippers.
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