![a0b04cd6-Australia Sydney International Tennis](https://a57.foxnews.com/static.foxnews.com/foxnews.com/content/uploads/2018/09/1200/675/09c7cb7c56374a01260f6a70670034d6.jpg?ve=1&tl=1)
Slovakia's Dominika Cibulkova returns a shot to Poland's Agnieszka Radwanska during the women's final of the Sydney International tennis tournament in Sydney, Australia, Friday, Jan. 11, 2013. Radwanska won the match 6-0, 6-0. (AP Photo/Rob Griffith) (The Associated Press)
MELBOURNE, Australia – Agnieszka Radwanska has won her 10th consecutive match of 2013, defeating Australian wild-card entry Bojana Bobusic of 7-5, 6-0 in the first round at the Australian Open on Monday.
The No. 4 -seeded Radwanska captured the Sydney International title on Saturday, beating Dominika Cibulkova of Slovakia 6-0, 6-0 a week after winning a WTA tournament in Auckland, New Zealand. The 23-year-old Radwanska has 12 career singles titles.
Bobusic was serving for the first set at 5-4, but Radwanska broke in that game and again in the 12th to take the first set and start a dominating roll in the second.