Sharapova advances at Indian Wells

Indian Wells, CA ( - Maria Sharapova beat Victoria Azarenka in a match between former No. 1 players Monday night at the BNP Paribas Open.

The second-seeded Sharapova posted a 6-4, 6-3 victory to reach the fourth round. She won this tournament in 2006 and 2013 and lost to Azarenka in the 2012 final.

Sharapova's next opponent will be defending champion Flavia Pennetta. The 15th-seeded Italian defeated 21st-seeded Australian Samantha Stosur 6-4, 6-2.

Former Indian Wells champion and No. 4 seed Caroline Wozniacki lost 6-4, 6-4 to 31st-seeded Swiss Belinda Bencic. Wozniacki titled here in 2011 and was a runner-up twice.

Bencic, 18, failed to win a game off Wozniacki last year in Istanbul.

The teenager will face 2010 Indians Wells champion Jelena Jankovic in the fourth round. The 18th-seeded Serbian rallied to beat 16th-seeded American Madison Keys 5-7, 6-4, 6-3.

No. 5 seed Ana Ivanovic of Serbia, the 2008 Indian Wells winner, was beaten 6-2, 5-7, 6-2 by 25th-seeded Frenchwoman Caroline Garcia.

Garcia will next play 24th-seeded German Sabine Lisicki, who beat 11th-seeded Italian Sara Errani a 6-4, 6-2.

Sixth-seeded Canadian star Genie Bouchard cruised into the round of 16 by getting past 30th-seeded American Coco Vandeweghe, 6-3, 6-2.

"I felt very solid today. That's important against player with big weapons -- I told myself to be ready for anything," Bouchard said. "She had some great serves and some great forehands, and I was just ready for that. I was really going to try and neutralize that and take my chances when I had them.

"I'm happy I was able to step in and attack whenever she let up a bit out there."

Up next for the 2014 Wimbledon runner-up Bouchard will be rising Ukrainian Lesia Tsurenko, who upended 20th-seeded Frenchwoman Alize Cornet 7-5, 1-6, 6-2.