Europe

Serena and Venus on court in women's semifinals at Wimbledon

  • Serena Williams of the U.S celebrates after beating Anastasia Pavlyuchenkova of Russia inter women's singles match on day nine of the Wimbledon Tennis Championships in London, Tuesday, July 5, 2016. (AP Photo/Ben Curtis)

    Serena Williams of the U.S celebrates after beating Anastasia Pavlyuchenkova of Russia inter women's singles match on day nine of the Wimbledon Tennis Championships in London, Tuesday, July 5, 2016. (AP Photo/Ben Curtis)  (The Associated Press)

  • Elena Vesnina of Russia returns to Dominika Cibulkova of Slovakia during their women's singles match on day nine of the Wimbledon Tennis Championships in London, Tuesday, July 5, 2016. (AP Photo/Tim Ireland)

    Elena Vesnina of Russia returns to Dominika Cibulkova of Slovakia during their women's singles match on day nine of the Wimbledon Tennis Championships in London, Tuesday, July 5, 2016. (AP Photo/Tim Ireland)  (The Associated Press)

  • Serena Williams of the U.S returns to Elena Vesnina of Russia during their women's singles match on day eleven of the Wimbledon Tennis Championships in London, Thursday, July 7, 2016. (AP Photo/Kirsty Wigglesworth)

    Serena Williams of the U.S returns to Elena Vesnina of Russia during their women's singles match on day eleven of the Wimbledon Tennis Championships in London, Thursday, July 7, 2016. (AP Photo/Kirsty Wigglesworth)  (The Associated Press)

Serena and Venus Williams will be back on court, separately, to play for a spot in the Wimbledon final.

Serena, a six-time champion at the All England Club, will be first on Centre Court against Elena Vesnina in the semifinals. Following that match, five-time Wimbledon champion Venus will take on Angelique Kerber.

The winners will play in Saturday's final.

But Serena and Venus won't be done after their singles, and neither will Vesnina. The American sisters will play in the doubles tournament on No. 2 Court later Thursday, taking on Vesnina and Ekaterina Makarova in the quarterfinals.